Open weburl in web component

[ctuxboy]

Hello,
i have a screen1, with a button.
I link the button to an ActivityStarter, that go to a webpage (url).
This works, only it opens an external browser
Is it possible when click the button, open the webpage (url) in the app itself (i think with the web(?) component)?

[Kumaraswamy]

If your using web-view components, then why should you use an activity starter? You could directly load the link.

[Alpha2020]

Use the WEB VIEWER component-

to open the url in your app.
Then use-

to go to any url.

[ctuxboy]

Thanks for your help
Sorry, it was a newbie question
Okay, try it, click on the button, but nothing happens

[TIMAI2]

Use the webviewer component, not the web component

[Alpha2020]

You have to use this component-

not Web component

[ctuxboy]

Oh okay,
Adding the WebViewer-component in Screen1, but it is 'visible' (below) , so adding Screen2 and adding there the Webviewer, but how open the link when click on the button in Screen1 and open it in the WebViewer on Screen2?

[Taifun]

@ctuxboy

how open the link when click on the button in Screen1 and open it in the WebViewer on Screen2 ?

what about making life easier and use only one screen?
see also tip 1 here

General Tips and Tricks for App Inventor

This list was made by @Taifun Use different screens wisely Before starting to create another screen, first you should think about is it really necessary? See also Building apps with many screens and SteveJG's post about advantages/disadvantages, because in only one screen you also can use vertical arrangements to simulate different screens, just set the arrangements to visible = true/false as needed... If you decided to use different screens, then you should switch them correctly, else you …

Taifun

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Trying to push the limits! Snippets, Tutorials and Extensions from Pura Vida Apps by Taifun.

[ctuxboy]

okay, now understand how can do this in one screen. with true/false the arrangements.
Thanks a lot for pushing me in the right direction
I try this method.